7x^2-287=0

Solution for 7x^2-287=0 equation:

7x^2-287=0

a = 7; b = 0; c = -287;
Δ = b2-4ac
Δ = 02-4·7·(-287)
Δ = 8036
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8036}=\sqrt{196*41}=\sqrt{196}*\sqrt{41}=14\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{41}}{2*7}=\frac{0-14\sqrt{41}}{14}
=-\frac{14\sqrt{41}}{14}
=-\sqrt{41}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{41}}{2*7}=\frac{0+14\sqrt{41}}{14}
=\frac{14\sqrt{41}}{14}
=\sqrt{41}
$